Find the area of a right angled triangle whose one side is 7cm long and length of hypotenuse is 25cm
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6
by Pythagoras Theorem on triangle ABC is a right angle triangle
(AB)²=(BC)²+(AC)²
(25)²=(7)²+(AC)²
(AC)²=(25)²-(7)²
(AC)=√(25)²-√(7)²
(AC)= √625-√49
(AC)=25-7
(AC)=18
(AB)²=(BC)²+(AC)²
(25)²=(7)²+(AC)²
(AC)²=(25)²-(7)²
(AC)=√(25)²-√(7)²
(AC)= √625-√49
(AC)=25-7
(AC)=18
Answered by
5
Given: a triangle ABC right angled at B BC=7cm
AB is the hypotenuse
AB^2=AC^2+BC^2
AB^2-BC^2=AC^2
25^2-7^2=AC^2
AC^2=625-49
AC^2=576
AC=✓576
AC=24
AB is the hypotenuse
AB^2=AC^2+BC^2
AB^2-BC^2=AC^2
25^2-7^2=AC^2
AC^2=625-49
AC^2=576
AC=✓576
AC=24
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