Find the area of a right angled triangle whose two legs are 7m and 8m
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Answered by
34
Area = {b × h}/2
= (7 × 8)/ 2 m
= 7 × 4 m
= 28 m^2
HENCE, THE AREA OF RIGHT ANGLED TRIANGLE 28 SQ.M
= (7 × 8)/ 2 m
= 7 × 4 m
= 28 m^2
HENCE, THE AREA OF RIGHT ANGLED TRIANGLE 28 SQ.M
Answered by
22
Area of Triangle = bh/2
Here b = Base = 7m , h = Height = 8m
Area of Triangle = 7*8/2
= 56/2
= 28 m sq
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