find the area of a right triangle ABC, right-angled at B in which base BC=24 cm and hypotenuse AC =25 cm. if BD perpendicular AC, find BD.
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Answer:
84CM SQUARE
Step-by-step explanation:
HYY... MATE ⬇️⬇️
AC SQUARE IS EQUALS TO A B SQUARE + BC SQUARE
THEN AB SQUARE IS EQUALS TO AC SQUARE MINUS BC SQUARE
A B SQUARE IS EQUALS TO 25 SQUARE - 24 SQUARE IS EQUALS TO 7 CM ( IT IS THE HEIGHT OF THE TRIANGLE)
THE AREA OF TRIANGLE IS EQUALS TO HALF INTO *BASE INTO* HEIGHT
THEREFORE
HALF INTO *BASE INTO *HEIGHT
THAT IS
1/2 * 24 * 7
= 84 CM SQUARE
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