Question

find the area of a right triangle having base = 24 and hypotenuse 25​

Answer 1

Solution :-

We know that :

$\small\red{\boxed{\sf{Area\ of\ right\ angle\ triangle = 1/2 \times base \times height (perpendicular)}}}$

&

$\small\red{\boxed{\sf{According\ to\ Pythagoras\ theorem\ : \:\:H² = P² + B²}}}$

Here,

Base (B) = 24 cm

Hypotenuse (H) = 25 cm

Now,

According to Pythagoras theorem....

$\small\sf\red{P² = H² - B²}$

$\small\red{\boxed{\sf{P = \sqrt{(H² - B²)}}}}$

$\small\red{\boxed{\sf{P = \sqrt{(25² - 24² )}}}}$

$\small\red{\boxed{\sf{P = \sqrt{(625 - 576)}}}}$

$\small\red{\boxed{\sf{ P = \sqrt{49}}}}$

$\large\red{\boxed{\sf{Perpendicular = 7 cm}}}$

Now,

$\small\red{\boxed{\sf{Area = 1/2 \times B \times P}}}$

$\small\red{\boxed{\sf{= 1/2 \times 24 \times 7}}}$

$\huge\bf\pink{= 84 cm²}$

Answer 2

Answer:

84^2

Step-by-step explanation:

area of triangle = 1/2 × b× h

but here we only have base = 24

and hypotenuse= 25

so we have to find height through Pythagoras theorem

= (base)^2 + (height)^2 = (hypotenuse)^2

= 24^2 + height^2 = 25^2

= 576 +height^2 = 625

= height^2 = 625-576 = 49

= height= √49 = 7

therefore, height = 7

so area = 1/2 ×b×h = 1/2 × 24×7 = 12×7 = 84^2

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