Question

Find the area of a right triangle, in which the sides containing the right angle measure 20 cm
and 15 cm​

Answer 1

Answer:

25

Step-by-step explanation:

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Answer 2

Step-by-step explanation:

$\huge\sf\fbox\red{ \: \: \: Question \: \: \: } :: -$

Find the area of a right triangle, in which the sides containing the right angle measure 20 cm and 15 cm

$\huge\sf\fbox\purple{ \: \: \: \:Given \: \: \: } :: -$

AB = C = 20cm

BC = A = 15cm

$\huge\sf\fbox\blue{ \: \: \: Required Solution \: \: \: } :: -$

$\triangle \sf{ \: ABC\: Right \: angle \: Triangle}$

Useing Pythagoras Therom :

$\sf \: Perpendicula {r}^{2} + Bas {e}^{2} = Hypotenus {e}^{2}$

$\longrightarrow(20)^2 + (15 {)}^{2} = \sf Hypotenus \\ \longrightarrow625 = \sf \: Hypotenus \\ \longrightarrow \sf \: 25cm = \sf \: Hypotenus$

We know the 3rd side Hypotenuse = 25

$\sf \: Semi \: Perimeter = \cfrac{15+ \cancel \red{20}+25}{ \cancel \red2} \\ \longrightarrow \cfrac{\cancel \blue60}{\cancel \blue2} \\➡ \red{30}$

Using Heron's Formula :

$\sf \: Area = \green{\sqrt{s(s - a)(s - b)(s - a)}} \\ \longrightarrow \sqrt{30(30 - 15)(30 - 20)(30 - 25)} \\ \longrightarrow 30 + 5 + 15 + 10 \\ \longrightarrow15 \times 2 \times 5 \times 3 \times 5 \times 2 \times 5 \\➡ \sf \red{ 15 {cm}^{2}}$

$\sf\underline\bold{Know \: More}:$

$\sf\underline \bold \pink{Formula \: Used}: -$

$\star\sf\underline \orange{Pythagoras \: Therom :}$

$\sf \: Perpendicula {r}^{2} + Bas {e}^{2} = Hypotenus {e}^{2}$

$\star \sf\underline \orange{Semi \: Perimeter :}$

$\sf \cfrac{A + B + C }{2}$

$\star\sf\underline \orange{ Heron's Formula }$

$\sf Area = {\sqrt{s(s - a)(s - b)(s - a)}}$

Hope it helpful...✌️

@Somya2563