Question

Find the area of a right triangle whose base is 1.2m amd hypotenuse 3.7m

Answer 1

area of right angle traingle = (1/2) x b x h sq. units
= (1/2) x 1.2m x 3.7m
= (3.7 x 0.6)m²
= 2.22m²

Answer 2

$\huge\boxed{\texttt{\fcolorbox{Red}{aqua}{Hey Mate!!!}}}$

$<b><i><font face=Copper black size=4 color=blue>$
Here is your answer
Hypotenuse = 3.7 m
Base = 1.2 m
Let the altitude is x m

By using Pythagoras Theorem we can calculate altitude

${(1.2)}^{2} + x {}^{2} = (3.7) {}^{2} \\ 1.44 + {x}^{2} = 13.69 \\ {x}^{2} = 13.69 - 1.44 \\ {x}^{2} = 12.25 \\ x = \sqrt{12.25} \\ x = 3.5 \: m$
So Altitude is 3.5 m

As we know the formula
Area of triangle is = 1/2(base)×(altitude)
$= \frac{1}{2} \times 1.2 \times 3.5 \\ = 0.6 \times 3.5 \\ = 2.1 \: m {}^{2}$

Therefore Area of triangle = 2.1 sq. m

$\large{\red{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\boxed{\underline{\underline{\underline{Hope\:it\: helps\: you}}}}}}}}}}}}}}}$

$<marquee>$

$\huge\red{Plzzz \:mark\:me\:as \: brainliest}$