find the area of a right triangle whose base is 1.2m and hypotenuse 3.7m
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this is the answer hope it helps you
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firstly used phytagoras theorm
h^2=p^2+b^2
3.7^2=p^2 + 1.2^2
p^2 =1.2^2 - 3.7 ^2
p=-12.25 root
then area of triangle 1/2 ×b×h
h^2=p^2+b^2
3.7^2=p^2 + 1.2^2
p^2 =1.2^2 - 3.7 ^2
p=-12.25 root
then area of triangle 1/2 ×b×h
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