Question

find the area of a right triangle whose base is 1.2m and hypotenuse 3.7m

Answer 1

Hypotenuse = 3.7 m

Base = 1.2 m

Perpendicular = sqrt ( H^2 - B^2)

= sqrt ( 3.7^2 - 1.2^2)

= sqrt ( 13.69 - 1.44)

= sqrt (12.22)

= 3.5 m


Area = Base *Perpendicular /2

= 3.5 * 1.2/ 2

= 3.5 * 0.6

= 2.1 m^2

Answer 2

$b = 1.2m \\ h = 3.7m \\ {p}^{2} = {h}^{2} - {b}^{2} = {(3.7)}^{2} - {(1.2)}^{2} = 13.69 - 1.44 = 12.25 \\ p = 3.5 \\ area = \frac{1}{2} \times b \times h \\ \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times 1.2 \times 3.5 \\ \: \: \: \: \: \: \: \: \: \: = 0.6 \times 3.5 \\ \: \: \: \: \: \: \: \: \: \: = 2.10 {m}^{2}$