Question

Find the area of a right triangle whose hypotenuse is 13cm and one side is 5cm​

Answer 1

Hey there!!❤️

Given,

H = 13cm

P = 5 cm

B = ?

By The Pythagoras theorem

H² = P² + B²

(13)² = (5)² + B²

B² = (13)² - (5)²

B² = 169 - 25

B² = 144

B² = (12)²

Comparing both sides we get,

B = 12

_____________________________

HOPE IT HELPS YOU❤️

Answer 2

Answer:

Area=$30cm^{2}$

Step-by-step explanation:

Given:

Hypotenuse = 13cm

Base = xcm(It is not given)

Height = 5cm

Using RHS:

$AB^{2}=AC^{2}+BC^{2}$

$13^{2}=5^{2}+x^{2}$

$169=25+x^{2}$

$169-25=x^{2}$

$144=x^{2}$

$\sqrt{144}=x$

∴$x=12$

To find Area:

Area=$\frac{1}{2}$×b×h

Area=$\frac{1}{2}$×12×5

Area=$30cm^{2}$