Find the area of a right triangle whose one leg and the hypotenuse is given.
One leg -5 cm
Hypotenuse-13cm
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by pythagoras theorem, hyp² = a² + b²
13² = 5² + b²
b² = 169 - 25
b² = 144
b = 12 units
then area = ab ÷ 2
= 5×12 ÷ 2
= 60 ÷ 2
= 30 square. units
13² = 5² + b²
b² = 169 - 25
b² = 144
b = 12 units
then area = ab ÷ 2
= 5×12 ÷ 2
= 60 ÷ 2
= 30 square. units
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