Question

find the area of a right triangle whose two sides are 24 cm and 7 cm and the perimeter is 56 cm​

Answer 1

Step-by-step explanation:

let the length of 3rd side be X

perimeter= sum of all sides

triangle have 3 sides

so, 56=24+7+X

X=25

from the sides we can observe that 25,24,7 are Pythagorean triplets [25^2=(24^2) +(7^2)]

=> it is a right angled triangle

so area of right angled triangle

(1/2)*b*h= (1/2)*24*7 = 12*7 = 84

therefore area = 84cmsq