Question

Find the area
of a right triangle whose two sides
are 24cm and 7cm and the perimeter
is 56cm. ​

Answer 1

Answer:

In one word answer :

Area = 84 cm²

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Answer 2

$\large\mathcal \red \bigstar{\underline{\purple{GIVEN:-}}}$

A Right angel Triangle( let ABC )

Two sides of length=24 cm and 7cm

Perimeter=56 cm

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$\large\bf\blue{To\:Find:-}$

Area of a Right angel Triangle.

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$\large\mathcal \red \bigstar{\underline{\pink{Formula}}}$:-

$there \: are \: two \: formula \: to \: find \: area \\ 1). \frac{1}{2} \times base \times height \\ \\ 2) \sqrt{s(s - a)(s - b)(s - c)}$

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$\large\mathcal \red \bigstar{\underline{\green{SOLUTION}}}$:-

WE WILL USE 1ST FORMULA:-

$1) \frac{1}{2} \times base \times height$

3rd side=perimeter-(sum of 1st and 2nd sides)

➠56-(24+7)

➠56-31

➠25

Height =7

Base=24

Area=1/2 ×h×b

=1/2 × 24 ×7

=12×7

=84 cm^2......

$\large\mathcal \red \bigstar{\underline{\pink{Answer}}}$➠

84 cm^2