find the area of a right triangle with hypotenuse 10 cm and base 6 cm
Answers
Answered by
90
By Pythagoras theorem
perpendicular =x
hypothesis ²=base²+perpendicular ²
10²=6²+x²
100=36+x²
x²=64
x=8
Area of triangle=1/2 base ×height
area of triangle=1/2×6×8
area of triangle=24cm²
perpendicular =x
hypothesis ²=base²+perpendicular ²
10²=6²+x²
100=36+x²
x²=64
x=8
Area of triangle=1/2 base ×height
area of triangle=1/2×6×8
area of triangle=24cm²
Answered by
22
area=1/2×base × height
=1/2×6×(√10²-6²)=3×(√64)=3×8=24cm2
=1/2×6×(√10²-6²)=3×(√64)=3×8=24cm2
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