Question

Find the area of a right triangle with hypotenuse 10 cm and base 5cm

Answer 1

Correct Question..

Find the area of a right triangle with hypotenuse 10 cm and base 6cm.

Solution..

by using Pythagoras theorem

$\tt \pink{ {CB}^{2} = {AB}^{2} + {AC}^{2}}$

AB = 5 cm

CB = 10 cm

AC = ?

$\tt{ ={CB}^{2} = {AB}^{2} + {AC}^{2}}$

$\tt {= {10}^{2} = {6}^{2} + {AC}^{2}}$

$\tt{= 100 = 36 + {AC}^{2} }$

$\tt {= {AC}^{2} = 100 - 36 }$

$\tt {= {AC}^{2} = 64}$

$\tt {= AC = \sqrt{64}}$

$\tt {= AC = 8 }$

Area of triangle = $\tt { \frac{1}{2} × Base × height }$

$\tt {= \frac{1}{2} × 6 × 8}$

$\tt {= \frac {48}{2}}$

$\tt {= {24cm}^{2}}$

Answer 2

Correct Question..

Find the area of a right triangle with hypotenuse 10 cm and base 6cm.

Solution..

by using Pythagoras theorem

\tt \pink{ {CB}^{2} = {AB}^{2} + {AC}^{2}}CB

2

=AB

2

+AC

2

AB = 5 cm

CB = 10 cm

AC = ?

\tt{ ={CB}^{2} = {AB}^{2} + {AC}^{2}}=CB

2

=AB

2

+AC

2

\tt {= {10}^{2} = {6}^{2} + {AC}^{2}}=10

2

=6

2

+AC

2

\tt{= 100 = 36 + {AC}^{2} }=100=36+AC

2

\tt {= {AC}^{2} = 100 - 36 }=AC

2

=100−36

\tt {= {AC}^{2} = 64}=AC

2

=64

\tt {= AC = \sqrt{64}}=AC=

64

\tt {= AC = 8 }=AC=8

Area of triangle = \tt { \frac{1}{2} × Base × height }

2

1

×Base×height

\tt {= \frac{1}{2} × 6 × 8}=

2

1

×6×8

\tt {= \frac {48}{2}}=

2

48

\tt {= {24cm}^{2}}=24cm

2

24 is your answer hope it help you