find the area of a ring whose outer and inner radii are 19 cm and 16 cm respectively
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2
Answer:
Step-by-step explanation:
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Formula used:
πr1²[19cm]+πr2²[16cm]
Solution:
Area [πr1²]:
22 x 19 x 19/7
= 22 x 361/7
= 7942/7
= 1134.57.....(i)
Area [πr2²]
22 x 16 x 16/7
=22 x 256 / 7
= 5632/7
= 804.57....(ii)
By equation (i)+(ii)_we get:
1134.57 + 804.57
= 1939.14(approx.)
[Calculator value: 1939.14285714]
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