Find the area of a rohmbus whose side is 6 cm and whose altitude is 4cm if one of its diagonal is 8 cm long, find the length of other diagonal
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Solution -
We know, rhombus is a parallelogram in some cases. So, we can use the same formula of parallelogram to find the area of rhombus
∵ Area of Rhombus = Area of ||gm
= [base × height]
∴ Area of rhombus
= [ 6 × 4 ] cm²
= 24 cm²
Let the other diagonal be x cm
According to Question,
Area of rhombus = 24 cm²
[∵ Area of rhombus = 1/2 × d1 × d2 ]
⇒ 1/2 × 8 × x = 24
⇒ 4 × x = 24
⇒ x = 24/4
⇒ x = 6
∴ Other diagonal = x cm = 6 cm
∴ Area of rhombus is 24 cm² and it's other diagonal is 6 cm
#Be Brainly
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here is your answer
The area of rhombus is base*height(since rhombus is a parallelogram. It means the area is 6*4cm^2 = 24 cm^2.
Now there is another formula for calculating the area of a rhombus . That is 1/2× diagonal1×diagonal2.
Using this we get
24=1/2×8×diagonal2
It means diagonal 2 is 6 cm in length (on solving).
The area of rhombus is base*height(since rhombus is a parallelogram. It means the area is 6*4cm^2 = 24 cm^2.
Now there is another formula for calculating the area of a rhombus . That is 1/2× diagonal1×diagonal2.
Using this we get
24=1/2×8×diagonal2
It means diagonal 2 is 6 cm in length (on solving).
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