Question

find the area of a rombhus if the measure of each side is 26cm and one of its diagonal is 48cm​

Answer 1

Answer:–

480 cm²

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Explanation:—

• The diagonal AC divides the rhombus ABCD into two equal triangle ABC and ACD.
• Area of quadrilateral ABCD = Area of ∆ ABC + Area of ∆ ACD

= 2 × Area of ∆ ABC

.

For ∆ ABC, we have

S = $\dfrac{26\:+\:26\:+\:48}{2}\: =\:50\:cm$

.

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)}$

$= \: \sqrt{50 \times 24 \times 24 \times 2}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:240\:cm²$

Area of quadrilateral ABCD = 2 × Area of ∆ ABC = 480 cm²

Answer 2

Step-by-step explanation:

480 cm

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Explanation:—

The diagonal AC divides the rhombus ABCD into two equal triangle ABC and ACD.

Area of quadrilateral ABCD = Area of ∆ ABC + Area of ∆ ACD

= 2 × Area of ∆ ABC

.

For ∆ ABC, we have

S =

$\dfrac{26\:+\:26\:+\:48}{2}\: =\:50\:cm$

Area of triangle =

$\sqrt{s(s - a)(s - b)(s - c)} </p><p>s(s−a)(s−b)(s−c)$

=

$\: \sqrt{50 \times 24 \times 24 \times 2}= </p><p>50×24×24×2$

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\:\:240\:cm²$

Area of quadrilateral ABCD = 2 × Area of ∆

ABC = 480 cm²

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