Question

find the area of a sactor of a circle with radius 6cm if angle of the sactor is 60 degree​

Answer 1

Step-by-step explanation:

we know that ,

area of sector :

$\frac{thetha}{360 } \times \pi \: r ^{2}$

given: theta= 60°

radius( r) =6 cm

putting these values in the formula :

$\frac{ 60}{360 } \times \frac{22}{7} \times {6}^{2}$

=

$\frac{132}{7} cm {}^{2}$

thank you!!!!

Answer 2

SOLUTION:-

Given:

•Radius of the sector of circle= 6cm.

•The sector of angle= 60°= theta.

To find:

The area of sector of circle.

Explanation:

Using the formula of the area of sector of circle:

$Area \: of \: sector = \frac{ \theta}{360} \times \pi {r}^{2}$

So,

$Area \: of \: sector = \frac{60}{360} \times \frac{22}{7} \times 6cm \times 6cm \\ \\ Area \: of \: sector = \frac{1}{6} \times \frac{792}{7} \\ \\ Area \: of \: sector = \frac{132}{7} {cm}^{2} \\ \\ Area \: of \: sector = 18.85 {cm}^{2}$

Thus,

The area of the sector of circle is 18.85cm².