Question

find the area of a sector of a circle with
radius 6 CM if angle of the Sector is 60'
(Take a € 22/7)​

Answer 1

Answer:

area of a sector =Φ/360*(πr^2)

(60/360)*(22/7)*6*6

(1/6)*(22/7)*6*6

22*6/7

132/7

Answer 2

Step-by-step explanation:

$\mathfrak{ \huge{ \green{ \underline{given}}}} \\ \mathfrak{ \large{ \red{radius \: = \: 6 \: cm}}} \\ \mathfrak{ \large{ \red{angle \: of \: sector \: (θ) = {60}^{o}}}} \\ \mathfrak{ \huge{ \green{ \underline{to \: find}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: ?}}} \\ \mathfrak{ \huge{ \green{ \underline{formula \: to \: be \: used}}}} \\ \mathfrak{ \large{ \red{area \: of \: sector \: = \: \frac{θ}{360} \: \times \: \pi {r}^{2} }}} \\ \mathfrak{ \huge{ \green{ \underline{solution}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \frac{θ}{360} \times \pi {r}^{2}}}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{60}{360} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{1}{6} \times \frac{22}{7} \times 6 \times 6 }}} \\ \mathfrak{ \large{ \blue{area \: of \: sector \: = \: \frac{22}{7} \times 6}}} \\ \mathfrak{ \large{ \orange{ \underline{area \: of \: sector \: = \: \frac{132}{7} {cm}^{2} }}}}$