Question

Find the area of a sector of a circle with radius 6 cm if angleof the sector is 60°

Answer 1

Given radius = 6 cm and angle = 60.

Area of sector = $\frac{60}{360} * \frac{22}{7} * (6)^2$

$= > \frac{1}{6} * \frac{22}{7} * 36$

$= > \frac{22 * 6}{7}$

$= > \frac{132}{7}$

$= > \boxed{18.85cm^2}}$

Hope this helps!

Answer 2

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$\color{indigo}{Required \: Answer}$

Let to be OBCD be a sector of the circle making 60° angle at centre O of the circle.

Now,

Area of sector of angle θ =

∅/360°× π(r)²

Now.,

Area of sector=

60°/360°×22/7×(6)²

1/6×22/7×6×6=132/7

Note:- Cancel 6 and 6

Therefore, the area of the sector of the circle making 60° at the centre of the circle is (132/7)

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