find the area of a sector of a circle with radius 6cm if angle of the sector is 60°?
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Step-by-step explanation:
here r=6 cm and theta=60°
therefore
the area of a sector=theta/360×πr^2
=60°/360°×22/7×6×6 cm^2
=22/7×6 cm^2
=132/7 cm^2
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