Question

Find the area of a sector of radius 7 cm and central angle is 45°? ​

Answer 1

Answer:

Class 10th, chapter 12,

Areas related to circle

Step-by-step explanation:

Area of a sector with angle theta and radius r is given by:-

$\frac{theta}{360} \times \pi {r}^{2}$

Here, theta = 45°,

R = 7 cm

So, area of the sector is given by:-

$\frac{45}{360} \times \pi \times {7}^{2} \\ = \frac{1}{8} \times \frac{22}{7} \times 7 \times 7 \\ = \frac{77}{4} \\ = 13.75 \: {cm}^{2}$

That's the answer.

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