find the area of a sector whose are length is 25π cm and angle of the sector is 60
Answers
Answered by
5
Heya
Arc length = 25π cm
angle = 60⁰ or π/3
so radius = r = 25π/π/3
=> r = 75cm
we know area of sector is given by Ф/360 πr²
so just plug in the values
we get
area of sector = 60/360 × 22/7 × (75)²
=> 2946.4 cm²
or 0.294 m²
Arc length = 25π cm
angle = 60⁰ or π/3
so radius = r = 25π/π/3
=> r = 75cm
we know area of sector is given by Ф/360 πr²
so just plug in the values
we get
area of sector = 60/360 × 22/7 × (75)²
=> 2946.4 cm²
or 0.294 m²
Answered by
7
Given that :
arc of length = 25π
Angle of sector = 60°
First We have find radius
r = 25π/π/3
r = 75
So we know that area of sector = theta/360Πr²
= 60/360× 22/7 × (75)²
= 2946.4 cm²
arc of length = 25π
Angle of sector = 60°
First We have find radius
r = 25π/π/3
r = 75
So we know that area of sector = theta/360Πr²
= 60/360× 22/7 × (75)²
= 2946.4 cm²
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