Find the area of a semi-circle whose perimeter is
(i) 54 cm answer 173.25cm^2
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Answer:
perimeter of semi-circle = πr+ 2r
= r ( π+2)
= r (22/7 +2) = r ( 36/7)
According to the question, r * 36/7 = 54
by calculating, r = 21/2 cm.
Therefore, Area of semicircle
πr^2 * 1/2 = 22/7 * 21/2 * 21/2 * 1/2 = 693/4 cm =173.25 cm (answer).
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