find the area of a semicircle whose circumference is 18 m
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Circumference of semicircle= pi r
18=22/7 r
18×7÷22=r
63/11=r
Area of semicircle =pi r^2
=22/7 (63/11)^2
=22/7×63/11×63/11
=18×63/11
=103.01 m sq.
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Answer:
103.01 sq. m is the correct answer
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