Question

find the area of a semicircle, whose circumference is 18m​

Answer 1

Circumference of circle = 2πr

18 = 2πr

18/2 = πr

9 = πr

9 × 7/22 = r

63/22 = r

2.86 = r

Area of semicircle =

$\frac{\pi {r}^{2} }{4}$

$= \frac{3.14 \times 2.86 \times 2.86}{4}$

= 6.420

Answer 2

$\huge\bf{\underline\red{Answer \: ⇝}}$

Circumference of circle = 2πr

18 = 2πr

18/2 = πr

9 = πr

9 × 7/22 = r

63/22 = r

2.86 = r

Area of semicircle = 1/2 (π r2)

=22/7 (63/11)^2

=22/7×63/11×63/11

=18×63/11

=103.01 m sq.