Question

Find the area of a shombus whose base is 14 cm and height is 9 cm

Answer 1

Answer:

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Step-by-step explanation:

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Answer 2

GivEn:-

• Base of rhombus = 14cm

• Height of rhombus = 9cm

To find:-

• Area of rhombus

SoluTion:-

✩ RHOMBUS

$\setlength{\unitlength}{0.83cm}\begin{picture}(12,4)\thicklines\put(7,8.9){ A }\put(12.6,8.9){ D }\put(5.6,5.9){ B }\put(11.2,5.9){ C }\put(5.4,7.5){14\;cm}\put(8,5.6){14\;cm}\put(6,6){\line(1,0){5}}\put(7.5,9){\line(1,0){5}}\put(12.5,9){\line(-1,-2){1.5}}\put(6,6){\line(1,2){1.5}}\end{picture}$

$\dag\;{\underline{\boxed{\bf{\pink{Area\;of\;rhombus = Base \times Height}}}}}$

$:\implies\sf 14 \times 9$

$:\implies{\underline{\boxed{\bf{\blue{126\;cm^2}}}}}$ ★

$\dag$ Hence, Area of rhombus is 126cm².

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Additional Information:-

• Diagonal of rhombus are perpendicular to each other.

• diagonals of Rhombus bisect opposite angles.

$\begin{lgathered}\boxed{\begin{minipage}{9cm}\bf\underline{ Important formulae of Cuboid}\\ \\ \textsf{ \bullet\ Area (using \: diagonal)\;= \dfrac{1}{2} \times d_1 \times d_2 }\\ \\ \textsf{ \bullet\ Area (using\:base\:and \: height)= (Base \times Height) } \\ \\ \textsf{ \bullet\ Area(using \: Trigonometry) = b^2 \times sin(a) } \\ \\ \textsf{ \bullet\ Perimeter (using \: sides) = 4a }\end{minipage}}\end{lgathered}$

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