find the area of a sqare, the length of whose diagonals is 25 cm
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Step-by-step explanation:
Let the side length of the square be x.
Now,
As we now all angles are 90° in a square,
Applying pythagoras theorem
p²+b² = h²
x² + x² = 25² cm²
=> 2x² = 625 cm²
=> x = 25/√2 cm
Area = side² = (25/√2 cm)² = 625/2 cm² = 312.5 cm²
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