Find the area of a square if the length of its sides is doubled.Also find the ratio of new area to its previous area.
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Area = (a)² ...(original)
Second condition, second side = 2a
So, second area = (2a)² = 4a²
Ratio of both the areas
= a²/4a²
= 1/4
i.e., 1:4
Second condition, second side = 2a
So, second area = (2a)² = 4a²
Ratio of both the areas
= a²/4a²
= 1/4
i.e., 1:4
simransahu94:
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let the side of the square be x
area of the square = x^2
now the side is doubled
hence new side= 2x
new area = ( 2x) ^2
=4x^2
ratio both the areas = x^2 : 4x^2
=1:4
hope it helps
plzz mark as brainliest
area of the square = x^2
now the side is doubled
hence new side= 2x
new area = ( 2x) ^2
=4x^2
ratio both the areas = x^2 : 4x^2
=1:4
hope it helps
plzz mark as brainliest
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