find the area of a square if the perimeter is equal in area to two square whose sides are 12 m and 5m respectively.
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* Area of 1st square,A1 = (a1)²
= (12 m)²
= 144 m²
* Area of 2nd square,A2=(a2)²
= 5² m²
= 25m²
Therefore, ATQ Perimeter of our ideal square is = A1+A2= 114+25 m²
p=4a° =139 m²
=>a° = 139/4 m² = 34.75 m²
now, area of the ideal square, A°= (a°)²
=> A°=(34.75 )²
A°= 1207.5625 m²
= (12 m)²
= 144 m²
* Area of 2nd square,A2=(a2)²
= 5² m²
= 25m²
Therefore, ATQ Perimeter of our ideal square is = A1+A2= 114+25 m²
p=4a° =139 m²
=>a° = 139/4 m² = 34.75 m²
now, area of the ideal square, A°= (a°)²
=> A°=(34.75 )²
A°= 1207.5625 m²
Himanshu1629:
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