Question

Find the area of a square inscribed in a circle of radius 3.5 cm​

Answer 1

$Radius \:of \: the \:circle (r) = 3.5 \:cm \:(given)$

$Diameter \: of \:the \:circle (d) = 2r \\= 2\times 3.5 \:cm \\= 7 \:cm$

/* According to the problem given */

$\underline {A \:square \: inscribed \: in \: a \: circle }$

$Diagonal \: of \: the \: square\\ = Diameter \: of \: the \:circle \\= 7 \:cm$

$\boxed {\pink { Area \: of \: a \: square(A) =\frac{(diagonal)^{2}}{2}}}$

$A = \frac{7^{2}}{2}$

$\implies A = \frac{49}{2}$

$\implies A = 24.5 \:cm^{2}$

Therefore.,

$\red { Area \: of \: the \: square(A)} \green {= 24.5 \:cm^{2}}$

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Answer 2

Answer:

radius:-3.5 CM

diameter:-7CM(3.5×2)

diagonal of square=diameter of circle

diagonal of square:-7cm

area of square:- side×side

OR

diagonal×diagonal÷2

A of square:-7×7=49

49÷2= 24.5

Step-by-step explanation:

Ans:-24.5