Question

find the area of a square inscribed in a circle with radius 8cm. ​

Answer 1

Answer:

128 cm sq.

Step-by-step explanation:

radius =8cm diameter = 2*8=16cm .

Then let side of square be X so a/q Xsq + Xsq =16 sq so X sq =128 cm sq. 

Answer 2

128 cm²

Step-by-step explanation:

Solution

⇒The radius of circle =8 cm

⇒ diameter = 8 × 2 =16 cm

The diameter of circle = diagonal of square

= 16 cm

BD= 16 cm

CD =BC =side (assume)

Applying Pythagoras theorem, we have

DC²+ CB² =BD²

⇒$2(side) {}^{2} = 16 \times 16$

⇒$(side) {}^{2} = \frac{16 \times 16}{2} = 16 \times 8 = 128cm {}^{2}$

= 16×8=128 cm²

Area of square

=(side)² =128 cm