Question

Find the area of a square of side 21m.​

Answer 1

Given :-

• Side of a square is 21 m

To Find :-

• What is the area of a square

Formula Used :-

♣️ Area Of Square :

$\bigstar \: \color{magenta}{ \boxed{ \bf Area _{(Square)} \: = \: Side \times Side}} \color{black} \: \bigstar$

Solution :-

Given :

• Side of a Square = 21 m

According to the question by using formula we get,

$\implies \: \bf Area _{(Square)} \: = \: Side \times Side$

$\implies \: \sf Area _{(Square)} \: = \: 21 \: m\times 21 \: m$

$\implies \: \bf \red{Area _{(Square)} \: = \: {441 \: m}^{2} }$

∴ Hence, The area of a square is 441 m² .

$\:$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬

Answer 2

Question :-

• Find the Area of a Square, whose side is 21 meter .

Answer :-

• Area of Square is 441 m² .

$\rule {195pt}{2pt}$

Given :-

• Side of Square = 21 meter

To Find :-

• Area of Square = ?

Solution :-

As per the provided information in the given question, Side of a Square is given 21 meter . And, we have been asked to calculate the Area of a Square .

For calculating the Area, we will use Area of Square formula :-

• $\bf{Area \: of \: Square = ({side})^{2} }$

Therefore, by substituting the given values in the above Formula :-

$\dag \: \: \sf{ Area \: _{Square} \: = \:({side})^{2} }$

$\Longrightarrow \: \: \sf{Area \: _{Square} \: = \: {(21)}^{2} }$

$\Longrightarrow \: \: \sf{Area \: _{Square} \: = \: 21 \: \times \: 21}$

$\Longrightarrow \: \: \bf {Area \: _{Square} \: = \: 441}$

Hence :-

• Area = 441 m²

$\rule {195pt}{4pt}$

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Square} = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \bf{Area \: _{Rectangle} = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Triangle} = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Parallelogram} = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \bf{Area \: _{Trapezium} = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \bf {Area \: _{Rhombus} = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$