Find the area of a square of side (3p+4).
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Answered by
3
area = sidexside
= (3p+4)^2
= 9p^2+24p+16
= (3p+4)^2
= 9p^2+24p+16
Answered by
5
It is given that the side of the square is ( 3p + 4 ).
From the properties of squares, we know : -
Area of square = side²
Therefore,
Area of the square = ( 3p + 4 )²
Without using formula : -
Area of square = ( 3p + 4 )( 3p + 4 )
Area of square = 3p( 3p + 4 ) + 4( 3p + 4 )
Area of square = 9p² + 12p + 12p + 16
Area of square = 9p² + 24p + 16
With the use of formula : -
Area of square = ( 3p + 4 )²
We know, ( a + b )² = a² + b² + 2ab
Area of square = ( 3p )² + ( 4 )² + 2( 4 x 3p )
Area of square = 9p² + 16 + 24p
Hence,
Area of the square is 9p² + 16 + 24p.
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From the properties of squares, we know : -
Area of square = side²
Therefore,
Area of the square = ( 3p + 4 )²
Without using formula : -
Area of square = ( 3p + 4 )( 3p + 4 )
Area of square = 3p( 3p + 4 ) + 4( 3p + 4 )
Area of square = 9p² + 12p + 12p + 16
Area of square = 9p² + 24p + 16
With the use of formula : -
Area of square = ( 3p + 4 )²
We know, ( a + b )² = a² + b² + 2ab
Area of square = ( 3p )² + ( 4 )² + 2( 4 x 3p )
Area of square = 9p² + 16 + 24p
Hence,
Area of the square is 9p² + 16 + 24p.
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