Question

Find the area of a square park whose perimeter is 320m.​

Answer 1

Perimeter of square park = 320m

Area of square park = ?

Side of square park = ?

Perimeter of square = 4 × side

320m = 4 × side

320/4 = side

80m = side

Area of square = side × side

= 80 × 80

= 6400m²

Answer 2

$\underline {\textbf {\textsf{Question :-}}}$

• Find the Area of a square park, whose Perimeter is 320 meter .

$\underline{ \textbf { \textsf{Answer :-}}}$

• Area of Square is 6400 m² .

$\rule{191pt}{2pt}$

Given :-

• Perimeter of Park = 320 m .

To Find :-

• Area of Square = ?

Solution :-

• As per the given question, it is provided that, Perimeter of Park is 320 m . And we have to calculate the Area of Square .

➻ Formula Required :-

• $\sf{ Perimeter \: of \: Square = 4 \times side}$
• $\sf{Area \: of \: Square = (side)^{2} }$

➻ First, we will find Side of Square :-

$\dag \: \: \bf{Perimeter \: _{Square} = 4 \times side}$

$\Longrightarrow \: \: \sf{320 \: = \: 4 \: \times \: side }$

$\Longrightarrow \: \: \sf{side \: = \: \frac{320}{4} }$

$\Longrightarrow \: \: \bf{side \: = \: 80 \: m}$

➻ Now, let's find Area of Square :-

$\dag \: \: \bf{Area \: _{Square} \: = \: (side)^{2} }$

$\Longrightarrow \: \: \sf{Area \:_{Square} \: = \: (80)^{2} }$

$\Longrightarrow \: \: \sf{Area \: _{Square} \: = \: 80 \: \times \: 80}$

$\Longrightarrow \: \: \bf{Area \: _{Square} \: = \: {6400 \: m}^{2} }$

Hence :-

• Area of Square = 6400 m² .

$\rule{191pt}{4pt}$

$\begin{gathered}\begin{gathered}\boxed{\begin{array}{c} \\ \underline{ { \textbf {\textsf \red{ \dag \: \: More \: Formulas \: \: \dag}}}} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Square = Side \times Side} \\ \\ \\ \footnotesize\bigstar \: \sf{Area \: of \: Rectangle = Lenght \times Breadth} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Triangle = \frac{1}{2} \times Base \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Parallelogram = Base \times Height} \\ \\ \\ \footnotesize \bigstar \: \sf{Area \: of \: Trapezium = \frac{1}{2} \times [ \: A + B \: ] \times Height } \\ \\ \\ \footnotesize \bigstar \: \sf {Area \: of \: Rhombus = \frac{1}{2} \times Diagonal \: 1 \times Diagonal \: 2}\end{array}}\end{gathered}\end{gathered}$