Question

find the area of a square Park whose perimeter is 80 m
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Answer 1

Correct Question:-

find the area of a square Park whose perimeter is 80 m

Given:-

• Perimeter of square = 80 m

To Find:-

• Area of square

Solution:-

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathfrak{ \underline{ \green{Formula \: to \: calculate \: the \: perimeter \: of \: square}}}$

$\underline{ \boxed{ \mathfrak{ \star \: \: \: \: \: { \red{ \large{ perimeter = 4 \times side}}}}}}$

According to question,

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: \: \:4 \times side = 80}$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: \: \:side = \frac{80}{4}}$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: \: { \boxed{\blue{ \mathfrak{side = 20}}}}}$

$\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \mathfrak{ \underline{ \green{Formula \: to \: calculate \: the \: area\: of \: square}}}$

$\underline{ \boxed{ \mathfrak{ \star \: \: \: \: \: { \red{ \large{ area = side \times side}}}}}}$

According to question,

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: \: \:area = 20 \times 20}</p><p>$

$\large{ \sf \longmapsto \: \: \: \: \: \: \: \: \: \underline{ \boxed{ \blue{ \mathfrak{</p><p>area = 400 \: {m}^{2} }}}}}$

Hence:-

• The area of square is 400 m²

Answer 2

Step-by-step explanation:

Given: There is a park in the shape of a square whose perimeter is 80m.

Need to find: Area of the park ?

❏ In this question we know that there is a park in the shape of square whose perimeter is 80m. Here the sides of the square is not given. So first we will find the sides of the square using the formula of perimeter of square. Then we easily find the area of the square park after having the sides.

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__________________

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$\frak{\underline{\underline{\dag As\ we\ know\ that\ :-}}}$

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$\star\;\boxed{\sf{\pink{Perimeter_{(square)}\ =\ 4 \times side.}}}$

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$\bf {Here} \begin{cases} &\sf{Perimeter\ =\ 80m.} \\ &\sf{Side\ =\ ?} \end{cases}$

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Therefore,

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$\sf : \implies {Perimeter\ =\ 4 \times Side} \\ \\ \\ \sf : \implies {80\ =\ 4 \times Side} \\ \\ \\ \sf : \implies {\cancel \dfrac{80}{4}\ =\ Side} \\ \\ \\ \sf : \implies {20\ =\ Side} \\ \\ \\ \sf : \implies {\underline{\boxed{\purple{\bf Side\ =\ 20m.}}}}\bigstar$

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Hence,

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• Side of the square park is 20m.

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__________________

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$\boldsymbol{\underline{\bigstar According\ to\ the\ question\ :-}}$

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$\star\;\boxed{\sf{\pink{Area_{(square)}\ =\ Side \times Side.}}}$

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$\bf {Here} \begin{cases} &\sf{Area\ =\ ?} \\ &\sf{Side\ =\ 20m.} \end{cases}$

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Therefore,

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$\sf : \implies {Area\ =\ Side \times Side} \\ \\ \\ \sf : \implies {Area\ =\ 20 \times 20} \\ \\ \\ \sf : \implies {Area\ =\ 400\ sq.\ m.} \\ \\ \\ \sf : \implies {\underline{\boxed{\purple{\bf Area\ =\ 400m^2.}}}}\bigstar$

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$\sf \therefore {\underline{Hence,\ the\ required\ area\ is\ \bf 400m^2.}}$