Question

find the area of a square that can be inscribed as a circle of radius 8 cm​

Answer 1

Answer:

128 cm^2

Step-by-step explanation:

Let ABCD be the square inscribed by the circle.

∴OA=OB=OC=OD

ABC is a right angled triangle, as OA=8,OB=8

AB=8+8=16

According to Pythagoras theorem,

Square of hypotenuse = Sum of squares of other two sides.

AC^2 = AB^2+BC^2

As ABCD is a square all the sides are equal, AB=BC

AC^2 = 2AB^2

2AB^2 = 16

AB = 2root8

Area = 128cm^2

Answer 2

Step-by-step explanation:

If the radius is 8 cm then the diameter is 16 cm.

Diameter of circle = Side of square.

So side of square = 16 cm

So,

Area of square = ( 16 × 16 ) cm

= 256 cm^2

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