Question

Find the area of a square that has the same perimeter as a rectangle whose length is 48 m and the ratio of length to the breadth is 3:1.

Answer 1

here is your answer

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Answer 2

Answer:

1024m²

Step-by-step explanation:

The given ratio of length to breadth of the rectangle is 3:1 and its length is 48m.

So,

$\frac{48}{x} = \frac{3}{1}$

3x=48

x=16

Means, breadth of rectangle is 16m.

So, perimeter of rectangle = 2(l+b)

= 2(48+16)

= 2×64

= 128.

Given that square has also equal perimeter that of the rectangle.

Thus,

Perimeter of square = 4 × length

128=4×length

length = 32m

So, length of square is 32m.

Finally,

Area of square = (length)²

= (32)²

=1024m²

I hope it will help you....

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