Question

Find the area of a square, the length of diagonal is 2under root2 m.​

Answer 1

Answer :-

Area of the square = 4 m²

Given :-

The diagonal of the square = 2√2 m

To find :-

Area of the square

Solution :-

First we have to find the side of the square. Then, we will find the area of the square by using the value of the side of the square.

=> Diagonal of a square = side × √2

=> 2√2 m = side × √2

=> $\dfrac{2\sqrt{2} }{\sqrt{2} }$m = side

=> 2 m = side

=> Area of a square = (side)²

=> Area = (2 m)²

=> Area = 4 m²

More To Know :-

$\star$ Perimeter of square = 4 x side

$\star$ Perimeter of rectangle = 2(Length + Breadth)

$\star$ Diagonal of rectangle = $\sqrt{(Length)^2 +(Breadth)^2 }$

$\star$ Area of rectangle = Length × Breadth

Answer 2

$\Large{\underbrace{\sf{\purple{Required\:Answer:}}}}$

⛦ Given :-

• The diagonal of the square = 2√2 m

⛦ To find :-

• Area of the square

⛦ Solution :-

First we have to find the side of the square. Then, we will find the area of the square by using the value of the side of the square.

∵ Diagonal of a square = side × √2

⇒ 2√2 m = side × √2

⇒ $\dfrac{2\sqrt{2} }{\sqrt{2} }$m = side

⇒ 2 m = side

∵ Area of a square = (side)²

⇒ Area = (2 m)²

⇒ Area = 4 m²

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