Question

Find the area of a square, the length of whose diago
the length of whose diagonal is 18/2.
​

Answer 1

Answer:

324

Step-by-step explanation:

let the square has side abcd

with ac and bd diagonals

by pythagoras

ac2=ad2+dc2

by soving we have

ad=18

area of square =side2

=18×18

=324

Answer 2

Answer:

324 sq. units.

Step-by-step explanation:

Given, Length of Diagonal (d) = 18√2 units.

==> Length of other Diagonal is also equal to 18√2 units, since diagonals of a square are equal.

Now, Area of Square = (1/2) × d1 × d2

==> Area of Square = 1/2 × d²

==> Area of Square = 1/2 × 18√2 × 18√2 sq. units

==> Area of Square = 1/2 × 324 × 2 sq. units

==> Area of Square = 324sq.units

This is the area of square(324 sq. units)

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