Question

Find the area of a square,the length of whose diagonal is 25cm.

Answer 1

SOLUTION

TO DETERMINE

The area of a square length of whose diagonal is 25cm

EVALUATION

Let the length of the square = a cm

Then length of the diagonal = a√2 cm

So by the given condition

$\displaystyle \sf{a \sqrt{2} = 25}$

$\displaystyle \sf{ \implies \: a = \frac{25}{ \sqrt{2} } }$

Hence the required area of the square

$\displaystyle \sf{= {a}^{2} \: \: {cm}^{2} }$

$\displaystyle \sf{= { \bigg( \frac{25}{ \sqrt{2} } \bigg)}^{2} \: \: {cm}^{2} }$

$\displaystyle \sf{= \frac{625}{2} \: \: {cm}^{2} }$

$\displaystyle \sf{= 312.5 \: \: {cm}^{2} }$

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Answer 2

Answer:

312.5²

Step-by-step explanation:

area of square= 1/2×(diognal)²

=1/2×25×25

=312.5²