Question

Find the area of a square the length of whose
diagonalis 16 square

Answer 1

I won't understand the question clearly

Answer 2

if Q.

solution:-

• we know the all angles of square are of 90°

• all side of square are equal and diagonals are equal.

so,

let, diagonal is hypotenuse

now, by Pythagoras theorem

S = side.

=> (1st S)²+(2cd S)² =(Hypotenuse)²

=> x² + x² = (16)²

=> 2x = 16

=> x = 16/2

=> x = 8

length of sides of square are 8 cm.

=> Area of square = (side) × (side)

=> Area of square = 8 × 8

=> Area of square = 64 cm².

8 cm and 64 cm² are length of side and area of the square respectively.

i hope it helps you.