Question

find the area of a square tile whose side is 32 cm.
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Answer 1

Answer:

Hi there !!!!!

Here is your answer ⬇️⬇️⬇️

$area \: of \: square \: = {a}^{2}$

where a is its side

Therefore the are of the square tile is = 32*32

=1024sq.cm

Answer 2

Step-by-step explanation:

Question :-

• Find the area of square tile whose side is 32 cm.

To Find :-

• Area of square tile.

Solution :-

Given :

• Side = 32 cm

By using the formula,

${\longrightarrow{\sf Area\ of\ square\ =\ a^2}}$

Where,

• a = length of the side

According to the question, by using the formula, we get :

${\longrightarrow{\sf Area\ of\ square\ tile\ =\ a^2}}$

${\longrightarrow{\sf (32)^2}}$

${\longrightarrow{\sf 32 \times 32}}$

${\longrightarrow{\sf 1,024\ cm^2}}$

$\therefore$ Hence, area of square tile is 1,024 cm².

More To Know :-

$\boxed{\begin {minipage}{9cm}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {minipage}}$