Question

Find the area of a square where diagonal length is 14 cm​

Answer 1

☆Answer☆

$\huge\purple {98}^{2}$

☆EXPLANATION☆

Given,

The diagonal of a square = 14 cm

Let the side of square be x.

Then,

The diagonal of a square = 14 cm

√2 × side of square = 14 cm

√2 × = 14 cm

x = 14/√2 cm

x= 7√2 cm

Length of side of square = x= 7√2 cm.

Area of square = $\sf { side}^{2}$

Area of square = $\sf {x}^{2}$

Area of square = $\sf { 7√2}^{2}$

Area of square = $\sf {98}^{2}$.

$\fbox \red{Hence, area of square \: = {98²} }$

Answer 2

Answer:

$\huge \sf \colorbox {pink}{heya \: mate}$

Step-by-step explanation:

COMPLETE STEP BY STEP ANSWER :-

In a square ⬛, all 4 sides are equal , and here the length of square is 14 cm.

$\red{therefore \: ,\: AB=BE=CD=DA}$

all the angles of a square is 90⁰.

therefore, triangle ABC =90⁰.

ACCORDING T

according to Pythagoras theorm, in a right angled triangle PQR , right angled at Q, PQ²+QR²=PR².a

considering triangle ABC in square ABCD .

it's right angled at B , so applying Pythagoras theorm,we get :-

putting value of AB and BC , we get :-

$14² cm²+14² cm²=AC²$

$➜AC²=(14²+14⁴) cm$

$➜AC²=2×14²cm²$

taking square ropt on both sides of equation we get -:

$\sqrt{AC²} = \sqrt{2} \sqrt{14² cm²}$

here , canceling square root with whole square, we get :-

$AC = 14 \sqrt{2 \: cm}$

sorry the answer that is in above is for the sides of square , for correct answer refer to attachment ^^"