find the area of a square which can be inscribed in a circle of radius 8 cm
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Given radius = 8cm.
Then the diameter of a square = diagonal = 2 * 8
= 16cm.
Let the side of the square = xcm.
By Pythagoras theorem, we get
x^2 + x^2 = 16^2
2x^2 = 256
x^2 = 128cm^2.
Therefore the area of the square = 128cm^2.
Then the diameter of a square = diagonal = 2 * 8
= 16cm.
Let the side of the square = xcm.
By Pythagoras theorem, we get
x^2 + x^2 = 16^2
2x^2 = 256
x^2 = 128cm^2.
Therefore the area of the square = 128cm^2.
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