find the area of a square whose diagnol length is 3.6m.STEP BY STEP EXPLANATION,BRAINLIEST
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Diagonal=3.6m
OC=OD=1/2 × Diagonal
=1.8m (Diagonals of square are equal and bisect each other at 90°)
In right triangle ODC
OD^2 + OC^2 = side^2
side=√2×(1.8)^2
=1.8√2m
Area=(1.8√2)^2
=3.24×2
=6.48m^2
OC=OD=1/2 × Diagonal
=1.8m (Diagonals of square are equal and bisect each other at 90°)
In right triangle ODC
OD^2 + OC^2 = side^2
side=√2×(1.8)^2
=1.8√2m
Area=(1.8√2)^2
=3.24×2
=6.48m^2
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zebronics33:
bro any easy way i am not able to understand
but u will have to use Pythagoras theorem
Use Pythagoras theorem in triangle ABC and then calculate the side and then find the area
No other way bro
Than this one
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