Find the area of a square whose diagonal is 5 √2 cm
Answers
Answered by
0
Answer:
...............................
Attachments:
Answered by
0
Answer:
20 cm^2
Step-by-step explanation:
let square ABCD ,
AC is diagonal = 5√2
let , AB = x
by using pythagorus theorem ,
in ^ ABC ,
AC^2 = AB^2 + BC^2
x^2 + x^2 = 5√2 ^2
2x^2 = 5√2 × 5√2
2x^2 = 50
x^2 = 50/2
x^2 = 25
x = √25 :. x = 5
formula of area of square = 4 × side
= 4 × 5
= 20 cm^2
Similar questions