Question

find the area of a square whose diagonal is 5 root over 2 cm​

Answer 1

Step-by-step explanation:

$area \: of \: square = \frac{1}{2} \times {diagonal}^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times {5 \sqrt{2} }^{2} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{1}{2} \times 100 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 50 {cm}^{2}$

Answer 2

$\huge \orange{ \boxed{\mathfrak{solution}}}$

Given:

•Diagonal of square =

${ \boxed { \bold{5 \sqrt{2}} }}$

To find :

• Area of square :

As we know the formula of Area of square in terms of diagonal =

$\huge \red{\boxed{ \bold{\frac{1}{2} ( {d}^{2} )}}}$

put the value of( d )

$\rightarrow \: \frac{1}{2} ( {5 \sqrt{2} })^{2} \\ \\ \rightarrow \: \frac{1}{2} (100) \\ \\ \rightarrow \: 50$

Hence the area of square is

$\green{\boxed{ \bold{50 \: {cm}^{2} }}}$