Find the area of a square whose diagonal is 5 sqr 2 ?
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Let the side of square =x
By Pythagoras theorem,
(5√2)²=x²+x²
25*2=2x²
50/2 =x²
25=x²
√25=x
5=x
Now the side of square is 5
Then,
Area of square =side²
Here, area of square =5²
Area of square =25
I hope this will help you
-by ABHAY
By Pythagoras theorem,
(5√2)²=x²+x²
25*2=2x²
50/2 =x²
25=x²
√25=x
5=x
Now the side of square is 5
Then,
Area of square =side²
Here, area of square =5²
Area of square =25
I hope this will help you
-by ABHAY
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