Find the area of a square whose diagonal is
![\sqrt[5]{2} \sqrt[5]{2}](https://tex.z-dn.net/?f=+%5Csqrt%5B5%5D%7B2%7D+)
cm.
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Answer:
Step-by-step explanation:
Using the formulas
A = a^2
d = √2 a
Solving for A
A = 1/2d^2 = 1/2 * 5^2
A = 12.5
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